It is given that, the density of an object placed on the surface of water is 10 kgm-3 and the density of water is 10-3 kgm-3. What will be the relative density of the object?
Answer (1)
5th Nov, 2021
Given :
Density of object = 10 kgm -3
Density of water = 10 -3 kgm -3
To find : Relative density of object
Formula for Relative density 🡪 Relative density =Density of object/Density of water
=10kgm -3 /10-3kgm -3
=0.01
Hence, relative density of object is 0.01
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