I've got 55.00 percentile in paper-2.What could my rank be?
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Hie ...
as you scored 55.00 percentile in paper-2,you rank may be in between 10k-20k
this is an expected rank not an exact rank,the rank depends up on number of candidates appeared in that exam ,it will also be dependent on the 10+2 percentage secured by you...so even if this year paper was little easier than last year then your rank my be expected in between 7k-10k......
all the best
thank you
Dear aspirant,
Your rank will be nearly (100-55)*145386/100=65415 based on previous year statistics.And chances are less to be qualified and appear for jee advanced exam as experts predicted cutoff to be nearly 85 percentile for general candidate.
Good luck
Your percentile is not enough to get into good colleges.The expected rank for your percentile is calculated based on the formula:
Rank=(100- NTA percentile)*145386/100.
Your expected rank may be 65,423(approximately).
This rank may vary after the official results which will be released in the month of April.
So please wait for the official cut offs and prepare well for the exam.
Hope you understood and if you have any questions please contact us.
Thank you!!
Since till now only the percentile has been declared by the NTA authorities and about the rank it is going to be declare at the end of the April month i.e after the completion of JEE mains paper 2 entrance exam but anyways below the link is given through which you can predict your rank via predictor where you can get the rough estimation of your rank.
https://engineering.careers360.com/jee-main-architecture-rank-predictor
https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning/amp
All the best
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