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Hi!
"NO" you have to in top 2 percentile for Cs or It in NITS
Total Student -9.65 lakh
Your 88.7 percentile
88.7 % of 9.65 lakh=8,55,955
9,65,000-8,55,955=1,09,045 appox your rank
B.Tech/B.Arch Admissions OPEN
Hello
Greetings
Your percentile is 88.7 It means 88.7% student of the Total student appeared for the Exam are Behind You Therefore 11.3% students of the Total students appeared for the exam are Ahead of You, Therefore Your calculated rank is 98815
Your Rank would change Either Your Percentile Score is Increases in the next attempt or Number of Student increases in the Next attempt the Number of Student Increases to 1400000 and Your percentile remains same then Your New rank would be 158200
As per Your current Performance, You may be eligible for JEE Advance But the final cutoff will be released once the JEE Main April gets Over
If Your Percentile Score Increases in the Next attempt Then Your Rank would Be calculated By the Following Formula
(100 - your total percentile score (Higher of two)) X Student appeared in JEE Main/100
At this rank It is Not possible to get admission into any NIT, In Open category Please try better in the next attempt of JEE Main
You should Try to get more than 98 percentile for NIT
Hope this Helps All the Best
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