#IT
83 Views

j equivalent to magnitude of jE divided by E vector , ......what does it mean


Aditya Singh 28th Nov, 2020
Answer (1)
Ayush 28th Nov, 2020

Hi Candidate,

The current density vector "j" is the vector whose magnitude is the electric current density, and whose direction is the same as the motion of the positive charges. The current density is the amount of charge per unit time.

The term "E" refers to the Electric Field which is experienced due to the movement of charges in an conductor. The term of magnitude of JE divided by E, refers to J as- I J.E I/ IEI and is equivalent to "j".

Hope that this answer helps you. Have a Good Day!!

Related Questions

UPES Integrated LLB Admission...
Apply
Ranked #28 amongst Institutions in India by NIRF | Ranked #1 in India for Academic Reputation by QS University Rankings | 16.6 LPA Highest CTC
ICFAI-LAW School BA-LLB / BBA...
Apply
Ranked 1 st among Top Law Schools of super Excellence in India - GHRDC | NAAC A+ Accredited | #36 by NIRF
Great Lakes PGPM & PGDM 2025
Apply
Admissions Open | Globally Recognized by AACSB (US) & AMBA (UK) | 17.3 LPA Avg. CTC for PGPM 2024 | Application Deadline: 1st Dec 2024
Chandigarh University Admissi...
Apply
Ranked #1 Among all Private Indian Universities In QS Asia Rankings 2025 | Scholarships worth 210 CR
Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates, and judiciaries
ISBR Business School PGDM Adm...
Apply
250+ Companies | Highest CTC 16 LPA | Average CTC 8 LPA | Ranked as Platinum Institute by AICTE for 6 years in a row | Awarded Best Business School...
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books