Question : Jitin's age 3 years from now will be double the average of Jitin's current age and his age 8 years ago. What was Jitin's age 5 years ago?
Option 1: 7 years
Option 2: 8 years
Option 3: 11 years
Option 4: 6 years
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Correct Answer: 6 years
Solution :
Let $x$ be the current age of Jitin.
Average of Jitin's current age and his age 8 years ago
= $\frac{x + (x-8)}{2}$
= $\frac{2x-8}{2}$
= $x-4$
Jitin's age 3 years from now = 2 × average
⇒ $x+3 = 2(x-4)$
⇒ $x+3 = 2x - 8$
⇒ $x = 11$
Jitin's age 5 years ago
= $x-5$
= 11 – 5
= 6
Hence, the correct answer is 6 years.
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