Question : John got 20% marks in an examination and failed by 10 marks. In the same examination, Jack got 35% marks which were 20 more than the minimum passing marks. Find the percentage of minimum marks required to pass.
Option 1: 30%
Option 2: 35%
Option 3: 25%
Option 4: 20%
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Correct Answer: 25%
Solution :
Given: John got 20% marks and failed by 10 marks.
Let the maximum marks be $x$.
According to the question,
⇒ $20$% of $x + 10 = 35$% of $x -20$
⇒ $\frac{7x}{20}-\frac{x}{5} = 10 + 20$
⇒ $\frac{15x}{100} = 30$
⇒ $x = \frac{30 × 100}{15}=200$
The minimum passing marks are (35% of 200 – 20)
$=\frac{35}{100} \times 200 -20 = 70 - 20=50$
So, the percentage of minimum marks required to pass $=\frac{50}{200} \times 100=25$%
Hence, the correct answer is 25%.
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