Question : Kapila is thrice as efficient as Vipul and together they can finish a piece of work in 30 days. In how many days Vipul alone can finish the work?
Option 1: 60 days
Option 2: 30 days
Option 3: 90 days
Option 4: 120 days
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Correct Answer: 120 days
Solution : Let the efficiency of Vipul as $x$ and the efficiency of Kapila as $3x$. The total efficiency of Kapila and Vipul working together = $x + 3x = 4x$ This means they can complete $4x$ the amount of work in one day. Given that Kapila and Vipul together can complete the job in 30 days. The total work to be done = \(30 \times 4x\) The time it would take for Vipul to complete the job alone = $\frac{30 \times 4x}{x}$ = 120 days Hence, the correct answer is 120 days.
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