kinetic and potential energy of electron present in second bhors orbit of hydrogen atom are respectivelyc(first bohrs orbit energ=-13.6
Answer (1)
8th Nov, 2020
Hello Geetanjali!
I am giving the solution to your question below:-
We have, |K.E|= (1/2 )|P.E|--------(i)
E= (-13.6)× (z^2/n^2) eV/atom
For n= 2, |K.E|= (-13.6)×1/4 = -3.4 eV/atom
Now, |P.E|=2×|K.E|= 2×(-3.4) = -6.8 eV/atom
Hence, the kinetic energy and potential energy of the electron present in the second orbit of Bohr's H-atom is -3.4 eV/atom and -6.8 eV/atom respectively.
Hope you are clear now!
Happy learning:)
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