Question : $\triangle $KLM is a right-angled triangle. $\angle$M = 90$^{\circ}$, KM = 12 cm and LM = 5 cm. What is the value of $\sec$ L?
Option 1: $\frac{13}{12}$
Option 2: $\frac{5}{12}$
Option 3: $\frac{12}{5}$
Option 4: $\frac{13}{5}$
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Correct Answer: $\frac{13}{5}$
Solution : By Pythagoras theorem, KL 2 = KM 2 + ML 2 ⇒ KL = $\sqrt{12^2 + 5^2}$ = $\sqrt {144+69}$ = $\sqrt{169}$ = 13 $\therefore\sec$ L = $\frac{\text{KL}}{\text{ML}}$ = $\frac{13}{5}$ Hence, the correct answer is $\frac{13}{5}$.
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