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Hi Sreeram,
You got 88.9 percentile in JEE main 2 exam, your rank would be approximately in between 12000 to 13000. Also, Above is the range of your possible rank. The predicted rank may vary due to JEE Main tie breaker rules for the same score. Also, you can check your expected rank using the formula:
Rank = (100-percentile)*(No. of students appeared for the examination)/100
As the no. of students appeared for Paper 2 are 112680, your rank will be around 12560. However as the no. of students in April changes, your rank will change according to that. On the basis of your percentile, you will get only private colleges:
Also, you can improve your rank in april exam. If you secured a rank below 3000, then there will be a great chance to geeting an NIT. All the best!!
You can also go through our college predictor to check which colleges you are eligible for through your JEE Mains score. The link for the college predictor is :
JEE Main Architecture/Paper-2 College Predictor - Know your college ad ...
Hi Sreeram.
With 88.9 percentile in January's JEE Mains 2020, you might get an estimated rank of around 96,000. This rank was calculated using the formula (100-88.9)*869010/100. You rank might increase if the number of students giving Mains in April increase.
Now, with this estimated rank, if you are of General category, you have NO chances of getting an NIT. Not even the lower-tier NITs. It is difficult for you to get GFTIs too. For more detailed analysis of the colleges that you might be able to get, check out this college predictor-
JEE Main College Predictor – Know your College Admission Chances Based ...
All the best.
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