length of a rectangle is 8m less than twice its breadth.if the perimeter of the rectangle 56m, find its length and breadth
Hi aspirant,
This is a very simple question which can be solved by applying basic fundamental of mathematics. Let the breadth of rectangle be b meters so according to the question the length would be 2b-8. Now the perimeter of of rectangle is given and as we know the formula of of perimeter is 2(l+b).
Therefore 2(b+2b-8)=56
6b-16= 56
6b= 72
b= 12
Show the breadth of rectangle is 12 m and length would be 16 meters.
Hope it helps!
Dear student,
Given perimeter = 56m
First you need to read the problem and form equations accordingly.
So let breadth be x then length will be according to question 2x-8.
Formula for the perimeter of rectangle = 2(l+b)
=2(2x-8+x) which is equal to 56.
Then 6x-16=56
= 6x=72
Value of x will be 12.
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