Question : Let A, B, and C be the mid-points of sides PQ, QR, and PR, respectively, of PQR. If the area of $\triangle$ PQR is 32 cm2, then find the area of $\triangle$ ABC.
Option 1: 24 cm2
Option 2: 16 cm2
Option 3: 32 cm2
Option 4: 8 cm2
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Correct Answer: 8 cm 2
Solution : Given: Let A, B, and C be the mid-points of sides PQ, QR, and PR, respectively of $\triangle$PQR, the area of $\triangle$PQR is 32 cm 2 . We know, Area of $\triangle$ABC = $\frac{1}{4}$ × (Area of $\triangle$PQR) So, the area of $\triangle$ ABC = $\frac{1}{4}$ × 32 = 8 cm 2 Hence, the correct answer is 8 cm 2 .
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