lines are perpendicular find combined eqn 3x2-4xy=0
Answer (1)
5th Aug, 2020
Hello dear,
Given equation is 3x^2-4xy=0
x(3x-4y) =0
separate equations of the lines are x = 0 and 3x-4y =0
let m1 and m2 be the slopes of these lines
then m1 does not exist and m2 =3/4
now, required lines are perpendicular to these lines
their slopes are -1/m1 and -1/m2
since m1 does not exist -1/m1 =0
also , m2 = 3/4 , -1/m2 =-4/3
Their combined equation is 4xy +3y^2 =0
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