Locus of the point of intersect in of tangents to the circle x^2+y^2=a^2 which makes complementary angles with x-axes is x^2-Y^2=0 how?

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Locus of the point of intersect in of tangents to the circle x^2+y^2=a^2 which makes complementary angles with x-axes is x^2-Y^2=0 how?

supriyamalldi 18th Sep, 2018

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Omisha sharma 22nd Sep, 2018

Hi,

Here only career related queries are solved not not physics chemistry maths or bio. You can go on google and search the related query. All the best!

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