Question : M is three times as good a worker as N and together they finish a piece of work in 30 days. In how many days will M alone finish the work?
Option 1: 50
Option 2: 40
Option 3: 60
Option 4: 45
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Correct Answer: 40
Solution :
Given: M is three times as good as N.
Let the efficiency of N and M be $x$ and $3x$ respectively.
So, total work $=30×(x+3x)=120x$ units
Therefore, the time required by A to finish the work alone = $\frac{120x}{3x}$ = 40 days
Hence, the correct answer is 40.
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