Question : Manoj decided to give 25% of his income to his son A and a certain amount to his son B. If he gave INR 2,208 to B which is 92% of the decided amount and INR 1,542 less than the amount given to A, then what percentage of his total income did Manoj decide to give his son B?
Option 1: 16%
Option 2: 12%
Option 3: 15%
Option 4: 20%
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Correct Answer: 16%
Solution : Given, A's share = 25% of Manoj's income B's share = Rs. 2208 = A's share - 1542 Let Manoj's income be $x$ ⇒ A's share = $\frac{25}{100}x$ = $0.25x$ Let B's decided share be $y$ ⇒ B's share = $2208$ = $\frac{92}{100}y$ ⇒ $y = \frac{2208}{0.92}$ ⇒ $y =$ Rs. 2400 According to the question, 2208 = A's share – 1542 ⇒ A's share = Rs. 3750 ⇒ $0.25x = 3750$ ⇒ Manoj income = $x$ = Rs. 15000 ⇒ Decided percentage for B = $\frac{2400}{15000}× 100$ = 16% Hence, the correct answer is 16%.
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