Masses 8kg, 2kg, 4kg and 2kg are placed at the corners A, B, C AND D respectively of a square ABCD of diadonal 80cm. The distance of th c
Answer (1)
Student Expert
27th Aug, 2019
Hello there!
Greetings!
Centre of mass is given by = (m1x1+m2x2+m3x3+m4x4)/(m1+m2+m3+m4)
where m is the respective mass and x is the respective distance with respect to A ( in metres)
the diagonal of a square is 0.8 metres therefore using pythogoras law each side is of a distance 0.56 metres.
therefore centre of mass is = (8*0+2*0.56+4*0.8+2*0.56)/(8+2+4+2)=0.34 metres from A.
thankyou
Greetings!
Centre of mass is given by = (m1x1+m2x2+m3x3+m4x4)/(m1+m2+m3+m4)
where m is the respective mass and x is the respective distance with respect to A ( in metres)
the diagonal of a square is 0.8 metres therefore using pythogoras law each side is of a distance 0.56 metres.
therefore centre of mass is = (8*0+2*0.56+4*0.8+2*0.56)/(8+2+4+2)=0.34 metres from A.
thankyou
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