Minimum marks I should take in JEE MAIN 2020 to get seat in NITK SURATKAL for CSE BRANCH ,my category OBC .
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Hello,
Here are the cut off ranks of NIT Suratkal of 2019:
Computer Science and Engineering
General category
Home state
Openning rank:928
Closing rank:3928
Other state
OR:278
CR:1767
OBC NCL
Home state
Openning rank:
877
Closing rank:
2237
Other state
OR:334
CR:663
SC
Home state
Openning rank:170
Closing rank:889
Other state
OR:181
CR:273
ST
Home state
Openning rank:228
Closing rank:344
Other state:
OR:116
CR:123
You can see the ranks and also for more information visit https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-surathkal
Thank you.
HELLO BHIMANNA!
DON'T JUST AIM FOR MINIMUM MARKS GO FOR MAXIMUM EFFORT THAT YOU CAN PUT THAT WOULD EVENTUALLY FETCH YOU GOOD MARKS. AND I WOULD SUGGEST YOY TO SCORE A 250+ IN JEE MAINS THAT WILL GET YOU A BRANCH OF YOUR CHOICE ANYWHERE.FOR MORE DETAILED RANK CUTOFF PLEASE VISIT https://engineering.careers360.com/articles/jee-main-cutoff
HOPE THIS HELPS!
ALL THE BEST!
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