minimum marks in jee mains for NIT rourkela for OBC candidate and home state?
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dear aspirant,
according to last year cutoff ranks in nit rourkela for OBC and home state if u are male candidate for civil engineering 16035 and for female 17167. for electrical engineering for male 17167 and for female 26185. for electronics comunication engineering for male 5709 for female 13556. for computer science engineering for male 4434 for female 10572. for more details u can check the below link:
https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-rourkela
OBC |
male-16035 |
female-17167 |
OBC |
male-10531 |
female-26185
OBC |
male-5709 |
female-13556
|
OBC |
male-9757 |
female-28910
OBC |
male-4434 |
female-10572
here is the link for your reference:
https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-rourkela
hope you clear the cut-off, All the best.
First of all, Now, marks does not play a direct role in getting admission into an NIT. Admission is given into any NIT on the basis of rank in the JEE Main exam.
However to get admission into NIT Rourkela, for a OBC candidate and that too from home state, percentile of 90-91 will be enough to get admission into a decent branch at NIT Rourkela.
Final prediction will be done after NTA announces the percentile for atleast Jan exam.
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