minimum pecentile to get csc branch in nit raipur by home state in obc
Dear aspirant.
The opening and closing rank for NIT RAIPUR in cse Branch is 7,431 - 10405 through counselling for general category. This analysis is based on previous years data and exper prediction. Cut off change every year , it depends on various factor like
No of seat available
No of students apper in exam.
Difficulty level of exam
You can check for the same
https://www.careers360.com/qna?=Unanswered-First .
You can read the article for details for state qota rank and cut off in NIT raipur.
https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-raipur . Thank you.
Or you can use college predictor tool for best option
https://engineering.careers360.com/jee-main-college-predictor?utm_source=qna&utm_medium=jee_cp
Hello Aspirant
According to previous year cutoffs, candidates up to 30,000 rank got admission with preferred branch in NIT. For an obc candidate, 92+ percentile would keep you on the safe side of admission in NIT.
Dear Student ,
As you know , admission through JEE MAIN is conducted only by the AIR (All India Rank) details only .So, as per previous year cut off trends , the closing rank of NIT Raipur for CSE (HS quota) and OBC caste , after 6th round of JOSAA counselling is as follows:
CR- 8331 (Gender Neutral)
CR-16417 (For Female category)
You can also find previous year cut off for NITs through this link:
https://engineering.careers360.com/articles/jee-main-cutoff-for-top-nits
Hope this information helps !
Best wishes !!
