Hi dear
In the JEE advanced eligibility criteria, nothing is given as such required percentile or anything.
Either you have cleared 12th or you are appearing 12th; you can apply for the exam.
But to appear for JEE Advanced. JEE mains score is a factor and in the JEE mains eligibility it is pretty clear min required percentage for general category is 75% and for other categories is 75%.
Hope it helps.
Hello Aspirant,
Joint Entrance Examination – Advanced (JEE-Advanced), formerly the Indian Institutes of Technology-Joint Entrance Examination (IIT-JEE) is an annual engineering college entrance examination in India.It is conducted by one of the seven zonal IITs (IIT Roorkee, IIT Kharagpur, IIT Delhi, IIT Kanpur, IIT Bombay, IIT Madras, and IIT Guwahati) under guidance of the Joint Admission Board ( JAB ).NTA will conduct JEE Main from 2019 onwards. But JEE Advanced is held by one of the seven Zonal Coordinating (ZC) IITs on a rotational basis, under the guidance of JAB every year.
Candidates satisfying all the following criteria are eligible to appear in JEE(Advanced).
IIT Roorkee, under the guidance of JAB, has scheduled JEE Advanced 2019 for May 19 (Sunday). As per the official announcement made at jeeadv.ac.in, the entire examination will be conducted in computer-based mode. The registration is expected to begin in May after the announcement of JEE Main Results.
Must have secured at least 75% aggregate marks in class 12 (or equivalent) Board examination.
Must be within the top 20 percentile of successful candidates in their respective class 12 (or equivalent) board examination.
Thank you!!
Hello,
Their is no percentage criteria.
The candidates should have appeared and qualified 12th standard (or equivalent) examination in 2018 or 2019.
Please note: Commencement of registration for JEE Advanced 2019 is from 1st week of may, 2019
for more information:
https://engineering.careers360.com/articles/jee-advanced
https://engineering.careers360.com/articles/jee-advanced-eligibility-criteria
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