MSRIT or Chandigarh university which is best for mechanical engineering
Hello aspirant,
Hope you're doing well.
Btech in mechanical engg is a four year full time undergraduate course offered to the students interested in mechanical sciences. Eligibility for the same is 10+2 with at least 75 percent aggregate in physics chemistry and maths subjects.
Coming to your query, i think Ramaiah institute of technology is better than chandigarh university for mechanical engineering. As, the placements are better there. Also, it is ranked much above chandigarh university. Although CHD university has a better infrastructure and a 200 acres campus, but placements are better at MSRIT. Median salary at chd university is 4.25 LPA, white at msrit, it is around 5.3 -5.5 LPA. I also compared both of these colleges. You may follow the link below for further assistance.
https://www.careers360.com/compare-colleges?college=326-3907-course=14580-71078
Hello,
MS Ramaiah university of applied science banglore, is a private university with 60 acre campus size and 2279 students intake with 380 faculty members. They have all the facilities like cafeteria, gym, wifi, library, etc.Their Mechanical engineering course is a 4 year full time course and requires kcet cutoff of 104168 rank. They have student ratings of 4.2/5. Their fees for the course is Rs 11.07 lakhs and median salary package offered is Rs 3.50 lakhs.
Chandigarh university, Chandigarh is also a private university with 1035 intake and 832 faculty members. They also have all the facilities except transport service. Their mechanical engineering course is also a full time 4 year course with fees of Rs 6.40 lakhs and median salary of Rs 4.25 lakhs. They have student rating of 4.1/5.
With this information you can select the best suitable college for you to know more about these colleges you can visit carers360 website.
To know which college you can get with your JEE mains score you can use careers360 college predictor tool
https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer