New: JEE Main 2025 Session 1 Result OUT; Check Now | Rank Predictor
JEE Main 2025: College Predictor | Marks vs Rank vs Percentile | Top NITs Cutoff
JEE Main 2025: January Session Official Question Paper for All Shifts | Exam Analysis
JEE Main 2025: High Scoring Topics | Sample Papers | Mock Tests | PYQs
Dinesh in order to get admission in Sastra there is no fixed cut-off. It is totally based on the 12th class percentage and Jee main marks. Your aggregate marks will be calculated with this formula: 12th percentage * 0.75+jee main mark * 0.25. Maximum marks which you can get is 165. Now on the basis of this aggregate marks a merit list will be prepared for all the students who are applying to pursue B.Tech degree from Sastra university and on the basis of your merit rank plus your stream priority you will be allotted the branch. Again there is no fixed cut-off for any branch but in order to get admission in the most demanding computer science branch according to past records your rank needs to be atleast in top 500.
B.Tech/B.Arch Admissions OPEN
Feel free to ask if you have any more queries. All the best!!
Know your college admission chances in NITs, IIITs and CFTIs, many States/ Institutes based on your JEE Main result by using JEE Main 2025 College Predictor.
Eligibility | Application | Preparation Tips | Question Paper | Admit Card | Answer Key | Result | Accepting Colleges
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile