My daughter got 98.7 Percentile in JEE mains B.Arch She is a female general candidate will she get admission in VNIT Nagpur
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Hello,
for jee main paper 2 , the predicted rank will be 1464. This rank will be changed as the april session of jee main paper2 is yet to be conducted.
for VNIT, nagpur the cutoff for female category is :-
for home quota:- 1070-1260. for other state quota the cutoff was :- 1120-1548. this is for the first round of counselling. In round 7, the cutoff for home state was :- 1250-1792 and for other state quota :- 1194-2615.
For special round 1:- cutoff was 1284-2331.
Your daughter can apply for it for sure and apply for other NIT campus too. She will surely get an admission at one of the campus of NIT.
For more details :- https://engineering.careers360.com/articles/jee-main-cutoff-for-vnit-nagpur
Hope it helps!
Her expected rank will be around 1464.Expected rank can be calculated using the formula (100-total percentile)*112679/100
112679 is the total number of candidates appeared in JEE main paper 2 January session
Her rank can be calculated as
(100-98.7)*112679/100=1464.
Cut off in 2019 for VNIT, Nagpur for B.arch is given below.The ranks are opening and closing ranks respectively (round 1)
- B.arch( home state): 1070- 1260
- B.arch(other state): 1120-1548
- b.arch(home state): 1250-1792
- B.arch(other state): 1194-2615
So with this it is expected that she may get seat in this college.But cut off is subjected to change it may increase or decrease depending on various factors like difficulty of paper, number of seats available, number of candidates appeared etc.
You can predict the college using college predictor
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