my jee main percentile is 97.56...which govt college can I get admission for cse or ece
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Hello Aspirant,
According to your score 97.556 percentile in JEE mains, your general category rank will be somewhere between 31,000 .
It is little difficult to get ECE, CSE branch in top NITs because getting a seat will depend on varies factors such as number of students applied for the same branch, performance of the students, category of the students, home state etc.
But you will get a chance in top NITs with decent branches. And you will get lower NITs with CSE, ECE branch.
Go through this link to get detailed information about total number of seats :
https://engineering.careers360.com/articles/nit-seat-matrix
Use the below link to get list of colleges that you can get based on your rank :
https://engineering.careers360.com/jee-main-college-predictor?utm_source=qna&utm_medium=jee_cp
check out the previous year's cutoff for NITs:
https://engineering.careers360.com/articles/jee-main-cutoff
You can also check out marks vs rank vs percentile from the below link:
https://engineering.careers360.com/articles/jee-main-marks-vs-percentile
Hope this information helps you.
Best Wishes!
HEY THERE!
So as you said your percentile in JEE MAINS 2022 is 97.56%ile and consequently your rank can vary nearly around ~38k ( this might vary according to official rank list). The prediction says you can get CSE or ECE in NITs or IIITs after 5 rounds of counselling or more. Some of the colleges based on previous year cutoffs are:
- NIT MIZORAM
- NIT NAGALAND
- NIT MANIPUR
There might be chances to get better NITs if you belong to some reservation category or you can also go for your home state NIT or other government engineering colleges.
If you could have mentioned your home state or category, then we would have suggested some more good colleges.
For now, you can use this college predictor link to know the answer to your query: https://engineering.careers360.com/jee-main-college-predictor?utm_source=clevertap&utm_medium=clevertap-sticky&utm_campaign=jee-main-qna-web-wap
thanks.
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