Answer (1)
ADITYA KUMAR Student Expert 13th Jun, 2020

Hi

With your percentile score,

your rank is given by


( 100-your percentile score ) * Total number of students that appeared in JEE mains January session /100.

= (100 - 82   )*869010 /100

=  156421

With this rank , you cannot get a seat in NIT Rourkela. For example,  last year a rank of 10531was required for OBC category for electrical engineering under home state quota in NIT Rourkela

So , to get into NIT Rourkela you need to get around 98.5 to 99 percentile in your JEE mains July session i.e around 170-180 marks

To prepare well for july session , follow the below tips:-

B.Tech/B.Arch Admissions OPEN

Apply to VIT - VITEEE 2025

Go through your syllabus  completing each chapter , you should go through mcqs and numericals of the same chapter

Make short notes of important formulas and concepts for each chapter and Keep revising it

Solve previous year JEE MAINS questions , it will let you know the examination pattern, type question etc so that you can prepare accordingly

Go through JEE MAINS mock test papers , it will let you know your preparation level and and weak areas so that you can work on them and perform well in your examination

To prepare well you can go for our jee mains knockout

https://learn.careers360.com/knockout-jee-main-april /

Thank you

2 Comments
Comments (2)
13th Jun, 2020
but food technology and bio medical has closing OBC rank was 40000...then?
Reply
Student Expert 13th Jun, 2020
Rohit rai To get a rank of around 40000 you need to score 95 percentile in your jee mains i.e around 110 marks
Reply
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