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As a total No. of 1,45,386 candidates had appeared for January Session, Using the Formula (100-your score)* 1,45,386 / 100- Your Expected rank will be 88,685. With this rank the chances seems less to get a seat in NITs. You can go through with the given below link to take an Idea about the previous year cutoff.
https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning
NOTE: This is only a prediction. NTA will merge the scores obtained in first and second attempt by candidates of JEE Main Paper 2 2019 for the compilation and preparation of overall merit/rank list. The rank will be released on 30th April, 2019.
Good Luck!
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