Hi

With   96.06 percentile

---------------------) Your crl rank will be roughly around  44k & obc rank 11k

Now,

Making  prediction is difficult as  cutoff  depends upon various factors like :-

-----------) number of students/ candidates  that appeared in the  jee main exam,

-----------) number of available seats,

-----------) jee main examination difficulty level.

-----------) the branch you want,

-----------) the category you belong etc.

-----------) your rank in jee main

But yes,

When we go through previous year trend then

>>>>>>>>> For your  rank

You have chances in following  which are listed below along with their closing rank in 6th round of josaa counselling 2020 under  all india quota   :-

----------) Indian Institute of Information Technology (IIIT) Nagpur:- cse:-11404 obc rank

-----------) Indian Institute of Information Technology (IIIT) Ranchi:- cse:- 12876 obc rank

-----------) Indian Institute of Information Technology(IIIT) Dharwad:- computer science:-14055 obc rank

-----------) Indian Institute of Information Technology(IIIT) Kalyani, West Bengal :- computer science :-14063 obc rank

-----------) Indian Institute of Information Technology Manipur:- computer science:- 15500 obc rank

And a few more

So, you should prefer above IIITs

You can check the closing ranks  at official website of josaa by going through the link given below

https://josaa.nic.in/Counseling/seatallotmentresult/currentorcr.aspx

Or

For previous year cut offs of top colleges like NITs, IIITs , you can also refer our page at :-

NITs :- https://engineering.careers360.com/articles/nits-cutoff-for-top-btech-branches

IIITs:- https://engineering.careers360.com/articles/jee-main-cutoff-for-top-iiits

Above prediction has been made  considering  past year cut off data but  closing rank for colleges varies every year depending upon many factors like jee main question paper difficulty, number of students writing the exam etc so

To have a personalised report on your chances of getting a college you can go through our college predictor, it will give you complete list of colleges which you can get on the basis of the category you belong to,  your home state, your gender etc, the link for  jee main college predictor is provided below

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

To help you  further,

To give an idea of jee main 2022 qualifying cut off ,

Minimum percentile in jee main 2021 to qualify it to be eligible for jee advanced is given below :-

--------) general :-87.8992241 percentile

--------) EWS:- 66.2214845 percentile

--------) OBC-NCL :- 68.0234447 percentile

--------) SC :- 46.8825338 percentile

--------) ST:- 34.6728999 percentile

--------) PWD :- 0.0096375 percentile

You can check the same at our page the link is provided below

https://engineering.careers360.com/articles/jee-main-cutoff

Thankyou

Hi aspirant...!

Hope you're doing great...!

So, with regard of you're query. For the percentile of 96.06, you'll get a general rank around 43174-33636. in OBC-NCL you'll  able to get a rank around below 10k. You can able to prefer IIIT Dharward, IIIT Kottamyam etc...

You can predict the NIT's and IIIT's  colleges   from the link that I am providing you below:

https://engineering.careers360.com/jee-main-college-predictor?utm_source=clevertap&utm_medium=clevertap-sticky&utm_campaign=jee-main-qna-web-wap

Hope this will helps you...!

Hello,

As far as your percentile is concerned , it's a good one. You can expect medium cut off IIITs like ranchi, kancheepuram, bhagalpur, bhuvaneshwar, jodhpur and a few more.

But mainly you will get core branches their and in non core electrical and electronics branch is possible . Rest depends on certain conditions like number of applicants appearing in the examination, number of vacant seats in college, previous years cut offs and difficulty level of the paper.

If you want to know about the colleges that you can get , you can have a look at the link given below -

https://engineering.careers360.com/jee-main-college-predictor?utm_source=qna&utm_medium=jee_cp