my jee paper 2 percentile is 96.04 what will be my marks

Hi Gagan,

Your exact marks can't be calculated as there is no criteria to do that. Roughly your marks word vary from 106 to 120.

According to the formula (100 - your total score) X 112679 /100 your estimated rank is coming out to be AIR 4462 which is a very decent rank for JEE- Main paper 2. Your overall rank can vary as the number of students appearing in the April attempt may increase or decrease.

You have not mentioned your category here. So these are cutoffs of 2019 for the General category of some top notch colleges to pursue B. Arch.

MNIT, Jaipur - AIR 940

MANIT, Bhopal - AIR 1807

NIT, Callicut - AIR 821

NIT Hamirpur - AIR 3934

NIT Patna - AIR 4686

NIT Raipur - AIR 3190

NIT Rourkela - AIR 1717

NIT Tiruchirappalli - AIR 1189

VNIT Nagpur - AIR 897

According to the cutoff ranks mentioned above, you are very close to ranks which are required for Getting admission into NITs. You can try for the state level colleges or some private institutions in your reach, you will surely get an  admission there. Or you can work hard for April attempt to score higher and get into a good institution.

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You may go through the link mentioned below for the JEE Main paper 2 college predictor to get the list of colleges you are eligible and don't forget to mention your category and Domicile state next time.

Link - JEE Main College Predictor

Good Luck!