My JEE paper2 2020 percentile is 95.5. what are my chances to get NIT Calicut. my home state is karnataka.
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Hello Baiju lal,
First of all congrats for your good score. for your percentile you can predict your rank by using the formula (100-your total percentile)*112679/100 and here 112679 is the number of students appeared for the exam. and after the april exam the number of candidates increases and the formula changes.
but for the now your rank might be around 5071 and you need to provide your category to know your colleges.
here i am providing you the college predictor link to get you to know your colleges.
and you can use the below link to know about the colleges:
https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning
the details in the above link are based on the previous years estimates and it might changes a little bit.
Hope it helps.
All the best.
To calculate your JEE main rank,you can use this formula ((100-your total percentile)*869010/100).This formula will give your general category rank(Common list rank).And your rank is approximately 39105
Since you are a not domicile of Kerala,you cannot avail the home state quota of NIT Calicut.You will come under the other state quota.The previous year's cutoff of NIT Calicut for different b.tech branches and categories is given in the below given website.
https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-calicut/amp
To know about all the possibilities of your admission into various colleges,visit the below given website.You will have to enter the details asked such as your percentile,category,home state etc..and the possibilities will be predicted.
https://engineering.careers360.com/jee-main-college-predictor
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