Hi!

"yes " You Will get good Nits

Total Student -9.65 lakh

Your 88.7 percentile

88.7 % of 9.65 lakh=8,55,955

9,65,000-8,55,955=1,09,045 appox your rank

check opening and closing rank by clicking below link

https://engineering.careers360.com/articles/jee-main-cutoff-for-top-nits

Hello Melchizedek..

According to careers360 rank formula,

Rank formula= [(100-total score) * (no of students wrote exam)] /100

No of students attended are 874469.

So your expected rank will be nearly around 98,815(we can't predict category rank).

As per previous year jee mains, any rank below 2,00,000 will be qualified for jee advanced.

So according to expected rank of yours, so you are eligible for jee advanced.

You will get good nit according to me, check previous years opening and closing rank on official josaa site.

Hope this helps you. All the best