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Hello Debalina,
Congratulations on scoring 91.11 percentile in JEE mains. Normally,the cutoff score for qualifying for JEE Advanced is around 100/360 ( for general category students) and around 2 lakh students qualify . So,roughly speaking,a score of 100 gives you a rank of about 2 lakh.
It also depends on how high you are aiming.If you want to go for NITs situated in the north east,a score of about 130–140 will be enough but if you are eyeing top NITs like NIT Trichy, you better rock the show and get 270+.Also,the cutoffs for IISc are insane,and usually about 290+.One more thing,there is a home state quota for the students of the particular state.
You can check the cutoffs of JEE-Mains for the previous 5 years to get an idea about them category-wise.Although ,the cutoffs might vary every year.
Thank you.
Hello Debalina
Congrats for your 91.11 percentile in JEE mains.
According to me 91.11 percentile is very good but you will not get the top 5 NIT 's because some people got 98 percentile so they deserve that but you can get seat in
National Institute of Technology, Jamshedpur, Jharkhand
National Institute of Technology, Kurukshetra, Haryana
Visvesvaraya National Institute of Technology, Nagpur, Maharashtra
National Institute of Technology, Patna, Bihar
National Institute of Technology, Rourkela, Orissa
National Institute of Technology, Srinagar, Jammu & Kashmir
Sardar Vallabhbhai National Institute of Technology, Surat, Gujarat
National Institute of Technology, Raipur, Chhattisgarh
National Institute of Technology, Agartala, Tripura
Indian Institute of Information Technology, Allahabad, Uttar Pradesh
you should try hard to get admission in this colleges.
I hope you get my point .
Thank You and GOOD LUCK!!!
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Thanks for contacting Careers360.
First of all congratulating you for your score.
Coming to your query, your rank is predicted to be between 77-78k according to my calculations.
With this rank or percentile, you have decent chances to get admitted in some of the NITs.
For the final rank list, you need to wait till April 30. The National Test Agency NTA will declare the combined result of both the exams (1st which was held in January and 2nd which is going to be held in April) after the declaration of result of 2nd exam i.e. after April 30. Afterwards the colleges under JEE Main will release their respective cutoffs.
Hope this helps.
Good luck!!
Hello Debalina Roy..
According to careers360 rank formula,
Rank formula= [(100-total score) * (no of students wrote exam)] /100
No of students attended are 874469.
So your expected rank will be nearly around 77,740.
As per previous year jee mains, any rank below 2,00,000 will be qualified for jee advanced.
So according to expected rank of yours, so you are eligible for jee advanced.
Hope this helps you. All the best
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