Hello Debapriya

Congrats for 94.12 percentile in JEE mains 2019.

This is preety good score and I think you should try some of the NIT's so that you would get admission. if you want CS branch in top NIT's then its tough,because there are people who have scored 98 or 99 percentile ,But you can  try.

List of NIT's in which you try are

• National Institute of Technology, Jamshedpur, Jharkhand

• National Institute of Technology, Kurukshetra, Haryana

• Visvesvaraya National Institute of Technology, Nagpur, Maharashtra

• National Institute of Technology, Patna, Bihar

  Recommended

• National Institute of Technology, Rourkela, Orissa

• National Institute of Technology, Srinagar, Jammu & Kashmir

• Sardar Vallabhbhai National Institute of Technology, Surat, Gujarat

• National Institute of Technology, Raipur, Chhattisgarh

• National Institute of Technology, Agartala, Tripura

• Indian Institute of Information Technology, Allahabad, Uttar Pradesh

I hope you get my point.

GOOD LUCK!!!

hii

to know the eligibility you have  get rank please find the below way

To calculate you rank you can use the formulae given below -

Rank=(total number of students -(percentile*0.01*number of students))

Where total number of students who appeared for the examination is 9.65 lakhs.

If You get below 224000 then you are eligible for JEE advance

regards