Answers (2)
Nihal Kumar Gupta Student Expert 21st Jan, 2020

Hi Surekha,

If you get 95.55 in JEE main exam, you rank would be approximately in between 75,000 to 80,000.  Also, Above is the range of your possible rank. The predicted rank may vary due to JEE Main tie breaker rules for the same score. You will not get NIT s with this marks and rank. For NITs, You have to secured minimum of 30,000 rank.

Also, you can check your expected rank using the formula:

(100-your total percentile) x 17,00,000/100, where 1700000 is the expected candidate in April session

So with 95.5 percentile, your rank would be around 75000.

If you have secured this rank you have a chance to get these colleges:

B.Tech/B.Arch Admissions OPEN

Apply to Amrita University B.Tech 2025

  • Walchand institute of technology
  • RAIT Mumbai
  • Pondicheery Engineering college
  • Vidyalankar institute of technology
  • Ujjain Engineering college
  • Amity University
  • PTU Punjab
  • MIT Academy Pune
  • UIET Punjab

These are few colleges, you will get on these marks. But you didn't get any NITs with this marks. You can also go through our college predictor to check which colleges you are eligible for through your JEE Mains score. The link for the college predictor is:

Muskan 21st Jan, 2020

Hi Surekha

It is difficult to predict your actual rank.

your expected rank can be calculated by the formula :

(100 - your percentile ) X 869010 / 100. If the no. of candidates increase in April session then instead of 869010 it would be no. of students appearing in that session.

Your expected rank will be approx. - 39105.45

You can refer to link below : https://engineering.careers360.com/articles/jee-main-rank-predictor

All the best !!!

Hope it helps :)


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