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My rank in JEE mains Was 16397 which branch I will get good branch on top NIT college


T Nagamani 19th May, 2019
Answers (3)
himanshi_1497963198 Student Expert 19th May, 2019

Hello T Nagamani

First thing the admission in the NIT also depends on the category to which you belong as there is differnt cut off for general or SC/ST category. As the cut off is not announced yet, so to determine your branch in the desired college can be determined by 2018 cut off

The following points will be taken into consideration for the NITs Cutoff for B.Tech Computer Science Engineering.

Number of applicants of the examination

Performance analysis of the applicants.

Number of questions asked in the examination.

Previous Year’s cutoff trends

Difficulty level of the examination.

You can get CSE branch in

  • NIT Agartala'
  • NIT Arunachal pradesh
  • NIT Andhra Pradesh
  • NIT Meghalaya
  • NIT Mizoram
  • NIT Nagaland

You can get ECE branch in NIT Jamshedpur and IT branch in NIT Raipur.

All the best!

Aditya Sharma Student Expert 19th May, 2019

Hey Aspirant.

See the rank u have secured is good enough for u to grab a seat in the good colleges like NITs IIITs or GFTIs for pursuing ur higher studies in the field of ur interest under the btech courses. U might not get good branches in top colleges but will surely get in the average ones. I m providing u a link for ur help.

https://engineering.careers360.com/jee-main-college-predictor?utm_source=C360&utm_medium=qna&utm_campaign=jee-main-college-predictor

Ask if any query. Good luck

1 Comment
Comments (1)
19th May, 2019
my category rank is 2741 and my crl is 9209 ..which nit i could get ??
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Sriya Bose Student Expert 19th May, 2019
Hello Aspirant!



In order to predict the colleges you can get based on your JEE Mains rank, use the Careers360 college predictor. The link for the college predictor is given below.



https://www.google.com/url?sa=t&source=web&rct=j&url=https://engineering.careers360.com/jee-main-college-predictor&ved=2ahUKEwjEhqvg4aXiAhUPaI8KHQfhBD8QFjABegQIAhAB&usg=AOvVaw1pTMu5LewXe0n3JPiA8V2U



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