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my son got 97.56 percentale in jee mains paper 2 does my son get a seat in nit


Answers (2)
Sanket Sanglikar 1st Feb, 2019


Hello Abhinav

congrats for scoring 97.56 percentile in JEE mains paper 2.

You have  performed extremely well  and from your percentile we can predict your rank.

There is a pedicted formula from our team to predict rank

Total No of students = 145386

Formula

Probable Rank= ( 100 - your NTA percentile ) x 145386 / 100

So your predicted rank  = 3547 approx

Our Team predicted that the qualify cutt off would be above 85 percentile .But it just a prediction .So pleae wait till april.


Your scores are really outstanding  so according to me you will get admission in following NIT's...

B.Tech/B.Arch Admissions OPEN

Apply to Amrita University B.Tech 2025

  • National Institute of Technology, Tiruchirapalli, Tamilnadu
  • National Institute of Technology, Warangal, Andhra Pradesh
  • National Institute of Technology, Surathkal, Karnataka
  • Moulana Azad National Institute of Technology, Bhopal, M.P
  • Motilal Nehru National Institute of Technology, Allahabad, U.P
  • National Institute of Technology, Calicut, Kozhikode, Kerala
  • National Institute of Technology, Durgapur, West Bengal
  • National Institute of Technology, Hamirpur, Himachal Pradesh
  • Malaviya National Institute of Technology, Jaipur, Rajasthan
  • Dr. B R Ambedkar National Institute of Technology, Jalandhar, Punjab


I hope you get my point.

Good Luck!!!

Abhinav p v 1st Feb, 2019

Dear parent

It's outstanding. The rank based on the score will be nearly (100-97.56) *145386/100=3547.And your son has chances with one of the NIT based on previous year trends.To know previous year cutoff, go to

https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning

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