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my son has scored 98.9 percentile in jee main 2 this year 2020 what college he is eligible


Answers (2)
Sujatha Venkat 3rd Feb, 2020

Hello,

Congrats for getting good percentile to your son. You haven't category and state.The cut offI'm giving you the link of last year cut of for all colleges,2019.

https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning/amp


This year total 112679 students attempted jee mains paper 2. You can calculate your approximate rank using formula h(100-percentile)*112679/100. That is 1,239. Your son will surely get an NIT . You can predict the colleges which your son gets through the below link

https://engineering.careers360.com/jee-main-architecture-college-predictor .

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Apply to Amrita University B.Tech 2025

Hope this is useful.

Yash Dev Student Expert 3rd Feb, 2020
Hello sir you can calculate the rank by for jee main paper 2 using the formula, (100-your total percentile) 112679/100.
In your case your son rank must be around 1240.
There's a total of 9 NIT's and 6 CFTIs and other institutes accepting jee main paper 2 scores for admission around 950 seats.

I request you to please help me with your category so that I can provide you exact information.

With this rank I guess you are not able to get admission in top colleges like SPA, Nit trichi.

But I belive you can easily get admission into NIT patna, Nit nagpur,indrapasth University.

Please use college predictor if you want to predict college on careers360 by clicking on the link mentioned below its very user friendly and very helpful.
https://engineering.careers360.com/jee-main-architecture-college-predictor

Feel free to comment if you have any doubt
Good luck
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