Question : N is the largest two-digit number which, when divided by 3, 4, and 6, leaves the remainder of 1, 2, and 4, respectively. What is the remainder when N is divided by 5?
Option 1: 4
Option 2: 2
Option 3: 3
Option 4: 1
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Correct Answer: 4
Solution : LCM of 3, 4, and 6 is 12. Common difference d = (3 – 1) = 2, (4 – 2) = 2 and (6 – 4) = 2 Since the common difference is the same, i.e., 2. The largest 2-digit number formed which is a multiple of 12 is 12 × 8 = 96 N = 96 – 2 = 94 So, when 94 is divided by 5, the remainder is 4 Hence, the correct answer is 4.
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Question : M is the largest 4-digit number which, when divided by 4, 5, 6, and 7, leaves the remainder as 2, 3, 4, and 5, respectively. What will be the remainder when M is divided by 9?
Question : A number $n$ when divided by 6, leaves a remainder of 3. What will be the remainder when $\left(n^2+5 n+8\right)$ is divided by 6?
Question : A number, when divided by 6, leaves a remainder of 3. When the square of the same number is divided by 6, the remainder is:
Question : When n is divided by 4, the remainder is 3. The remainder when 2n is divided by 4 is:
Question : Let $x$ be the least number which, when divided by 5, 6, 7, and 8, leaves a remainder of 3 in each case, but when divided by 9, leaves no remainder. The sum of the digits of $x$ is:
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