Question : $\angle A$ of $\triangle ABC$ is a right angle. $AD$ is perpendicular on $BC$. If $BC= 14$ cm and $BD= 5$ cm, then measure of $AD$ is:
Option 1: $2\sqrt5$ cm
Option 2: $\sqrt5$ cm
Option 3: $3\sqrt5$ cm
Option 4: $3.5\sqrt5$ cm
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Correct Answer: $3\sqrt5$ cm
Solution :
AD
2
= CD × BD
⇒ AD
2
= 9 × 5
⇒ AD
2
= 45
⇒ AD = $\sqrt{45}$ = $3\sqrt5$
Hence, the correct answer is $3\sqrt5$ cm.
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