Question : Of the 3 numbers whose average is 22, the first is $(\frac{3}{8 })^{th}$ of the sum of the other 2. What is the first number?
Option 1: 16
Option 2: 20
Option 3: 22
Option 4: 18
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Correct Answer: 18
Solution : Let the first number, second number, and third number be $x, y$, and $z$ respectively. Given: $x = \frac{3(y+z)}{8}$ ⇒ $y+z = \frac{8x}{3}$ Now, the average of three numbers = 22 Sum of the numbers = 3 × 22 = 66 According to the question: $x+y+z = 66$ Putting the value of $y+z$, we get: $x+\frac{8x}{3} = 66$ $⇒11x = 66\times3$ $\therefore x = 18$ Hence, the correct answer is 18.
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Question : Of the three numbers whose average is 40, the first is $\frac{1}{3}$rd of the sum of the other two. What is the first number?
Question : The average of the first three numbers is double the fourth number. If the average of all the four numbers is 12. Find the 4th number.
Question : The average of 8 numbers is 18. If one of the numbers is excluded, the average becomes 20. Find the excluded number.
Question : The sum of the first 20 term of the series $\frac{1}{5×6}+\frac{1}{6×7}+\frac{1}{7×8}+....$ is:
Question : Simplify the following expression: [$\sqrt{25}$ + 12 ÷ 3 – {20 + (16 of 8 ÷ 16) – (54 ÷ 18 of $\frac{1}{2}$}]
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