Question : One liquid contains 20% of acid the other liquid contains 30% of acid. A can is filled with 7 parts of the first liquid and 3 parts of the second liquid. The percentage of the acid in the new mixture is:
Option 1: 13%
Option 2: 30%
Option 3: 14%
Option 4: 23%
Correct Answer: 23%
Solution :
Let the first liquid be $A$ and the second liquid be $B$.
The first liquid $A$ contains 20% acid, and the second liquid $B$ contains 30% acid
⇒ The total parts in the mixture are 7 + 3 = 10
So, the acid percentage in new mixture = $\frac{\text{Percentage of acid in A×Parts of A}}{\text{Total Parts}}$+$\frac{\text{Percentage of acid in B×Parts of B}}{\text{Total Parts}}$
= $\frac{20×7}{10}+\frac{30×3}{10}$
= $\frac{140}{10}+\frac{90}{10}$
= ${14}+{9}$
= ${23}$%
Hence, the correct answer is 23%.
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