One Mole of a monoatomic gas is mixed with 1 mole of a diatomic gas. The value of Y for the mixture is
Answer (1)
21st Apr, 2019
Fir Monotomic Gas
Cv=3(R)/2
Cp=5(R)/2
For Diatomic Gas
Cv=5(R)/2
Cp=7(R)/2
Then after Mixture.
Total Cv=(3(R)/2+5(R)/2)/2
=2(R)
Total Cp=(5(R)/2+(7(R)/2)/2
=3(R)
Then Cp/Cv= 3R/2R=1.5
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