Question : P takes twice as long as Q, or three times as long as R, to complete a task. If they work together, they can complete the task in two days. How long will it take Q to complete the task on his own?
Option 1: 8 days
Option 2: 6 days
Option 3: 5 days
Option 4: 7 days
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Correct Answer: 6 days
Solution : Given: Q is twice as efficient as P and R is thrice as efficient as P. If P does 1 unit of work per day, then Q will do 2 units per day, and R will do 3 units per day. Now, work done by them in one day = (P + Q + R) = 6 units Since they complete the task in 2 days, the total work = 2 × 6 = 12 units So, Q alone will complete the task in $\frac{12}{2}$ days = $6$ days Hence, the correct answer is 6 days.
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Question : P and Q together complete a job in $4 \frac{2}{5}$ days. R and S complete the same job in $4 \frac{8}{9}$ days. If P, Q, R, and S work together, how many days do they need to complete the same job?
Question : P, Q, and R can complete a piece of work in 10 days, 15 days, and 20 days, respectively. If they work together, in how many days can they finish the same work?
Question : P and Q together can do a job in 6 days. Q and R can finish the same job in $\frac{60}{7}$ days. P started the work and worked for 3 days. Q and R continued for 6 days. Then the difference in days in which R and P can complete the job is:
Question : P and Q together can complete a piece of work in 6 days. If P can alone complete the work in 18 days, the number of days required for Q to finish the work is:
Question : A can complete $\frac{1}{3}$rd of a task in 7 days and B can complete $\frac{2}{7}$th of the same task in 10 days. In how many days can A and B together complete the task?
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