Question : PA and PB are two tangents from a point P outside the circle with centre O. If A and B are points on the circle such that $\angle {APB}=100^{\circ}$, then $\angle {OAB}$ is equal to:
Option 1: $45^{\circ}$
Option 2: $35^{\circ}$
Option 3: $70^{\circ}$
Option 4: $50^{\circ}$
Correct Answer: $50^{\circ}$
Solution : According to the question, $\angle$APB = 100º Also, $\angle$ OAP = $\angle$ OBP = 90º (the angle between the tangent and radius at the point of contact is 90º) Since the sum of all angles of a quadrilateral is 360º. $\angle$ OAP + $\angle$ OBP + $\angle$ ABP + $\angle$ AOB = 360º ⇒ 90º + 90º + 100º + $\angle$ AOB = 360º ⇒ $\angle$ AOB = 360º – 280º = 80º Now, in triangle AOB, ⇒ $\angle$ AOB + $\angle$ OAB + $\angle$ OBA = 180º Let $\angle$ OAB = $\angle$ OAB = $x$ (both angles are equal since angles opposite to equal sides are equal) ⇒ 80º + $x$ + $x$ = 180º ⇒ 2$x$ = 100º ⇒ $x$ = 50º Hence, the correct answer is $50^{\circ}$.
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Question : PA and PB are two tangents from a point P outside the circle with centre O. If A and B are points on the circle such that $\angle \mathrm{APB}=128^{\circ}$, then $\angle \mathrm{OAB}$ is equal to:
Option 1: 72°
Option 2: 52°
Option 3: 38°
Option 4: 64°
Question : PA and PB are two tangents from a point P outside the circle with centre O. If A and B are points on the circle such that $\angle \mathrm{APB}=142^{\circ}$, then $\angle \mathrm{OAB}$ is equal to:
Option 1: 31°
Option 2: 58°
Option 3: 71°
Question : PA and PB are two tangents from a point P outside the circle with centre O at the points A and B on it. If $\angle A P B=130^{\circ}$, then $\angle O A B$ is equal to:
Option 1: 45°
Option 2: 50°
Option 3: 35°
Option 4: 65°
Question : Two equal tangents PA and PB are drawn from an external point P on a circle with centre O. What is the length of each tangent, if P is 12 cm from the centres and the angle between the tangents is 120$^\circ$?
Option 1: 24 cm
Option 2: 6 cm
Option 3: 8 cm
Option 4: cannot be determined
Question : P is a point outside a circle with centre O, and it is 14 cm away from the centre. A secant PAB drawn from P intersects the circle at points A and B such that PA = 10 cm and PB = 16 cm. The diameter of the circle is:
Option 1: 10 cm
Option 2: 13 cm
Option 3: 11 cm
Option 4: 12 cm
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