particle of masses100and300gram have position vector 2i+5j+13kand position vector of their centr of mass
Answer (1)
Student Expert
12th Apr, 2020
Hi ,
We have,
X coordinate = MX + MX / M + M
= (100 x 2) + (300 x -6) / 100 + 300
= 200 - 1800 / 400
= -1600 / 400
= -4
Y coordinate = MY + MY / M + M
= (100 x 5) + (300 x 4) / 400
= 500 + 1200 / 400
= 1700 / 400
= 4.25
Z coordinate= MZ + MZ / M + M
= (100 x 13) + (300 x -2) / 400
= 1300 - 600 / 400
= 700 / 400
= 1.75
Thus, position of Centre of Mass is
X=-4,
Y=4.25,
Z=1.75
I hope that this helps you
Thankyou
We have,
X coordinate = MX + MX / M + M
= (100 x 2) + (300 x -6) / 100 + 300
= 200 - 1800 / 400
= -1600 / 400
= -4
Y coordinate = MY + MY / M + M
= (100 x 5) + (300 x 4) / 400
= 500 + 1200 / 400
= 1700 / 400
= 4.25
Z coordinate= MZ + MZ / M + M
= (100 x 13) + (300 x -2) / 400
= 1300 - 600 / 400
= 700 / 400
= 1.75
Thus, position of Centre of Mass is
X=-4,
Y=4.25,
Z=1.75
I hope that this helps you
Thankyou
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