Particular integral of 'e' raise to the power e ki power x
Answer (1)
Student Expert
29th Jan, 2019
Hello Amit,
The solution to your question, using the exponential integral function, is Ei(e to the power x)+C.
If you do a substitution where u=e to the power x and thus du=e to the power x dx, your integrand becomes
e to the power u /u du, so the definition of the exponential integral can be applied and the integral becomes Ei(u)+C=Ei(e to the power x)+C.
Hope this helps.
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