period of sin(x+8x+27x+..... +n³x) is
Answer (1)
24th Aug, 2021
Hello there !
Hope you are doing fine.
f(x)= sin [{n*(n+1)/2}^2x]
period of f(ax+b) is T/|a|.
so, since period of sin is 2pi, the period of f(x) will be 8pi/[n*(n+1)]^2
Hope this helps.
Stay safe.
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