pipe A can fill a tank in half the time in which pipe B can fill the same tank if both pipes are opened simultaneously with takes 8 hours to fill the tank in how many hours can A alone fill the tank
Answer (1)
21st May, 2020
Hello there,
I know it's late but let's solve the problem.
Let time taken by,
Pipe A= x
Pipe B=2x
[Pipe A takes half the time so for easier calculation we take 2x.]
For work done in 1minute,
By pipe A= 1/x
By pipe B= 1/2x
By both pipe A and pipe B together = 1/480
According to the problem,
1/x + 1/2x = 1/480 [8*60=480mins]
Or, 3/2x = 1/480
Or, x= 720
720mins means 12hours.
Therefore, time taken by pipe A alone to fill the tank is 12hours.
Hope this answer helps you.
I know it's late but let's solve the problem.
Let time taken by,
Pipe A= x
Pipe B=2x
[Pipe A takes half the time so for easier calculation we take 2x.]
For work done in 1minute,
By pipe A= 1/x
By pipe B= 1/2x
By both pipe A and pipe B together = 1/480
According to the problem,
1/x + 1/2x = 1/480 [8*60=480mins]
Or, 3/2x = 1/480
Or, x= 720
720mins means 12hours.
Therefore, time taken by pipe A alone to fill the tank is 12hours.
Hope this answer helps you.
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