Question : Pipes P and Q can fill a tank in 12 hours and 36 hours, respectively. If both pipes are opened, then how much time (in hours) will it take to fill the tank?
Option 1: 9
Option 2: 8
Option 3: 10
Option 4: 7
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Correct Answer: 9
Solution : We have, Pipes P and Q can fill a tank in 12 hours and 36 hours. Part filled by P in 1 hour = $\frac{1}{12}$ Part filled by Q in 1 hour = $\frac{1}{36}$ Part filled by both P and Q together in 1 hour = $\frac{1}{12}+\frac{1}{36}$ = $\frac{3+1}{36}$ = $\frac{4}{36}$ = $\frac{1}{9}$ The total time needed to fill the tank by P and Q is 9 hours. Hence, the correct answer is 9.
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Question : Pipe P alone can fill a tank in 18 hours and Pipe Q alone can fill the same tank in 24 hours. If both the pipes are opened on alternate hours one at a time and pipe Q is opened for the first hour, then in how much time the tank will be full?
Question : Pipes A and B together can fill a tank in 10 hours. Pipes B and C together can fill the same tank in 12 hours. Pipes A and C together can fill the same tank in 15 hours. In how many hours can pipe B alone fill the same tank?
Question : Three pipes A, B, and C can fill a tank in 6 hours, 9 hours, and 12 hours, respectively. B and C are opened for half an hour, and then pipe A is opened. The time taken by the three pipes together to fill the remaining part of the tank is:
Question : Two taps P and Q can fill a tank alone in 10 hours and 12 hours respectively. If the two taps are opened at 9 a.m., then at what time should the tap P be closed to fill the tank at exactly 3 p.m.?
Question : Tap A can fill an empty tank in 8 hours if no other tap is open, and tap B can empty the same tank, when filled, in 12 hours, when no other tap is open. Find the time taken to fill the same tank, when empty, if both the taps are opened together.
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