Question : PQR is an equilateral triangle. MN is drawn parallel to QR such that M is on PQ and N is on PR. If PN = 6 cm, then the length of MN is:
Option 1: 3 cm
Option 2: 6 cm
Option 3: 12 cm
Option 4: 4.5 cm
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
Correct Answer: 6 cm
Solution :
Given: PQR is an equilateral triangle and MN is drawn parallel to QR
MN || QR
∴ $\angle$PMN = $\angle$PQR and $\angle$PNM = $\angle$PRQ
By AAA-similarity,
$\triangle$PMN ~ $\triangle$PQR
So, $\angle$PMN will also be an equilateral triangle.
⇒ MN = PN = PM = 6 cm.
Thus, PN = 6 cm
Hence, the correct answer is 6 cm.
Related Questions
Know More about
Staff Selection Commission Combined Grad ...
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Get Updates Brochure
Your Staff Selection Commission Combined Graduate Level Exam brochure has been successfully mailed to your registered email id “”.
